Answer:

lui $13, 0x0004
lw  $12, 0x10($13)

After the lui instruction $13 contains 0x00040000. To get to the address we need, use an offset of 0x10.

Filling in the bottom Half

Part of Memory

By using the lui instruction, the base register can be loaded with multiples of 0x00010000. But often you want a more specific address in the base register. Use the ori instruction to fill the bottom 16 bits. Recall that:

ori d,s,imm

zero-extends imm to 32 bits then does a bitwise OR of that with the contents of register $s. The result goes into register $d.

QUESTION 10:

Say that memory is as above. The lw instruction (below) loads the word at 0x0060500C into $12.

lui $13, 0x

ori $13, $13, 0x

lw  $12, 0xC($13)

Complete the instruction sequence so that the base register contains the address 0x00605000 .